f(x+1)=4x^2-4x+5

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Solution for f(x+1)=4x^2-4x+5 equation: 


Simplifying
f(x + 1) = 4x2 + -4x + 5

Reorder the terms:
f(1 + x) = 4x2 + -4x + 5
(1 * f + x * f) = 4x2 + -4x + 5
(1f + fx) = 4x2 + -4x + 5

Reorder the terms:
1f + fx = 5 + -4x + 4x2

Solving
1f + fx = 5 + -4x + 4x2

Solving for variable 'f'.

Move all terms containing f to the left, all other terms to the right.

Reorder the terms:
-5 + 1f + fx + 4x + -4x2 = 5 + -4x + 4x2 + -5 + 4x + -4x2

Reorder the terms:
-5 + 1f + fx + 4x + -4x2 = 5 + -5 + -4x + 4x + 4x2 + -4x2

Combine like terms: 5 + -5 = 0
-5 + 1f + fx + 4x + -4x2 = 0 + -4x + 4x + 4x2 + -4x2
-5 + 1f + fx + 4x + -4x2 = -4x + 4x + 4x2 + -4x2

Combine like terms: -4x + 4x = 0
-5 + 1f + fx + 4x + -4x2 = 0 + 4x2 + -4x2
-5 + 1f + fx + 4x + -4x2 = 4x2 + -4x2

Combine like terms: 4x2 + -4x2 = 0
-5 + 1f + fx + 4x + -4x2 = 0

The solution to this equation could not be determined.

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